Answer:
Steps of construction- (i) Draw a line segment \[AB=6\text{ }cm\]. (ii) Draw a perpendicular bisector PQ of AB. (iii) Draw an arc at a distance 4 cm (from AB) intersecting PQ at C. (iv) Join CA and CB. Thus, \[\Delta \text{ }ABC\]is obtained. (v) Mark D on AB, such that \[AD=\frac{3}{4}AB=\left( \frac{3}{4}\times 6 \right)cm=\frac{9}{2}cm=4.5\,cm\] (vi) Draw \[DE\parallel BC\], cutting AC at E. Then, \[\Delta \text{ }ADE\] is the required triangle similar to \[\Delta \text{ }ABC\]such that each side of \[\Delta \text{ }ADE\] is \[\frac{3}{4}\] times the corresponding side of \[\Delta \text{ }ABC\].
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