10th Class Mathematics Solved Paper - Mathematics-2015 Delhi Term-II Set-I

  • question_answer
    In Fig. 6, find the area of the shaded region [Use\[\pi =3.14\]]

    Answer:

    Area of square (ABCD)
                            \[=14\times 14\]
                            \[=196\,\,c{{m}^{2}}\]
    Area of small square (EFGH)
                            \[={{(7-3)}^{2}}\]
                            \[=4\times 4=16\,\,c{{m}^{2}}\]
    4 (Area of semicircle) \[=4\times \frac{\pi {{r}^{2}}}{2}\]
                            \[=2\times 3.14\times 2\times 2\]
                            \[=25.12\,\,c{{m}^{2}}\]
    \[\therefore \] Required area (shaded) = Area of square\[\]Area of small square\[-4\times \]Area of semicircle
                            \[=(196-16-25.12)c{{m}^{2}}\]
                            \[=154.88\,\,c{{m}^{2}}\]


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