Answer:
We know that, \[co{{t}^{2}}\theta =cose{{c}^{2}}\theta -1\] \[={{\left( \frac{5}{4} \right)}^{2}}-1\] \[=\frac{25}{16}-1=\frac{25-16}{16}=\frac{9}{16}\] \[\Rightarrow {{\cot }^{2}}\theta =\frac{9}{16}\] \[\Rightarrow \cot \theta =\frac{3}{4}\]
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