Answer:
In \[\Delta \,ADE\] and \[\Delta \,ABC\] \[\angle DAE=\angle BAC\] [Common] \[\angle ADE=\angle ABC\] [Corresponding angles] By AA axiom \[\Delta \,ADE\sim \Delta \,ABC\] \[\therefore \frac{AE}{AC}=\frac{DE}{BC}\] [CPCT] \[\Rightarrow \frac{8}{8+2}=\frac{DE}{6}\] \[\Rightarrow 10\,\,DE=48\] \[\Rightarrow DE=4.8\,\,cm\]
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