Answer:
Given, \[{{E}_{s}}\]= 2, P = Rs. 8, Q = 200 units, \[{{Q}_{1}}\] = 250 units \[\therefore \,\,\Delta Q={{Q}_{1}}-Q=250-200=50\,\,units\] Let the change in price, \[\Delta P=x\] We know that, \[{{E}_{s}}=\frac{\Delta Q}{\Delta P}\times \frac{P}{Q}\] or \[\,2=\frac{50}{x}\,\,\times \,\,\frac{8}{200}=\frac{2}{x}\] or \[2x=2\] \[\Rightarrow \] \[x=1\] or \[\Delta P=1\] New price, \[{{P}_{1}}=P+\Delta P=8+1\] = Rs. 9
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