A) 145 m
B) 230 m
C) 260 m
D) 160 m
Correct Answer: C
Solution :
Time taken to cross second train \[=\frac{(250+x)\times 18}{102\times 5\times 18}\] Where, x = length of second train (in m) \[\Rightarrow \,\,\,\,\,\,\,\,\,\,5\times 18\times 102=18\times 250+18x\] \[\Rightarrow \] \[x=260\,\,m\]You need to login to perform this action.
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