A) \[100{}^\circ \]
B) \[120{}^\circ \]
C) \[40{}^\circ \]
D) \[150{}^\circ \]
Correct Answer: D
Solution :
\[x+\sqrt{3}y-6=0\] \[\sqrt{3y}=-x+6\] \[y=\frac{-1}{{{\sqrt{3}}^{x}}}+2\sqrt{3}\] Now, Slope\[=\frac{-1}{\sqrt{3}}\] Then, \[\tan \theta =\frac{-1}{\sqrt{3}}\] \[=\tan (180{}^\circ -30{}^\circ )\] \[=tan150{}^\circ \] \[\theta =150{}^\circ \]
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