A) 2500
B) 6696
C) 3536
D) None of these
Correct Answer: A
Solution :
\[186\times ~186+136\times ~136-2\times ~186\times ~136\] Let 186 be A and 136 be B then, \[{{(A-B)}^{2}}={{A}^{2}}+{{B}^{2}}-2\,\,AB\] \[{{(186-136)}^{2}}={{(50)}^{2}}=2500\]
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