A) \[100\,\,c{{m}^{2}}\]
B) \[110\,\,c{{m}^{2}}\]
C) \[120\,\,c{{m}^{2}}\]
D) \[150\,\,c{{m}^{2}}\]
Correct Answer: C
Solution :
Let length and breadth of the rectangle are l and b cm respectively. Then, \[{{l}^{2}}+{{b}^{2}}={{17}^{2}}=289\] .,.(1) And \[2\,\,(l+b)=46\] \[l+b=23\] ...(2) Area of the rectangle =\[l\times b\] \[=\frac{{{(l+b)}^{2}}-({{l}^{2}}+{{b}^{2}})}{2}\] \[=\frac{{{23}^{2}}-289}{2}\] \[=\frac{529-289}{2}\] \[=\frac{240}{2}=120\,\,c{{m}^{2}}\]
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