A) \[{{x}^{3}}+2{{x}^{2}}+4x+8\]
B) \[{{x}^{3}}+4{{x}^{2}}+2x+8\]
C) \[{{x}^{3}}-2{{x}^{2}}+4x-8\]
D) \[{{x}^{3}}+4{{x}^{2}}-2x-8\]
Correct Answer: A
Solution :
\[\frac{{{x}^{4}}-16}{x-2}=\frac{({{x}^{2}}-4)\,\,({{x}^{2}}+4)}{(x-2)}\] \[=\frac{({{x}^{2}}-4)\,\,({{x}^{2}}+4)}{(x-2)}\] \[=(x+2)\,\,({{x}^{2}}+4)\] \[={{x}^{3}}+2{{x}^{2}}+4x+8\]
You need to login to perform this action.
You will be redirected in
3 sec
