• # question_answer If${{(x+y-2)}^{2}}+{{(3x-2y-1)}^{2}}=0$ then the values of x and y are respectively? A) 1, 1       B) $1,\,\,-1$ C) $-1,\,1$                         D) $-1,\,\,-1$

If ${{(x+y-2)}^{2}}+{{(3x-2y-1)}^{2}}=0$ Then,$x+y-2=0$           ...(1) $3x-2y-1=0$                 ...(2) On solving eqn. (1) and (2) $x=+1,\,\,y=+1$