• question_answer A carpenter cuts a 13 m long board into length $1\frac{3}{4}$m,$2\frac{2}{3}$m,$3\frac{1}{6}$and$4\frac{1}{2}$m. How much board will be remaining after cutting the pieces? A) $\frac{11}{12}m$        B)   1 mC) 2 m                              D) 3 m

Total length the carpenter cuts $=\left[ 1\,\,\frac{3}{4}+2\,\,\frac{2}{3}+3\,\,\frac{1}{6}+4\,\,\frac{1}{2} \right]\,\,m$ $=\frac{145}{12}\,\,m$ now, board will be remaining, after cutting the pieces    $=13-\frac{145}{12}m$ $=\frac{156-145}{12}m$ $=\frac{11}{12}m$