A) 3 meters
B) 4 meters
C) 5 meters
D) 6 meters
Correct Answer: C
Solution :
Let breadth of a rectangle = b m Then, Area = \[12\,\,{{m}^{2}}\] \[l\times b=12\] \[4\times b=12\] \[b=3\,\,meters\] Now, diagonal of a rectangle \[=\sqrt{{{l}^{2}}+{{b}^{2}}}\] \[=\sqrt{{{(4)}^{2}}+{{(3)}^{2}}}\] \[=\sqrt{16+9}\] \[=\sqrt{25}=5\,\,m\]
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