A) \[\frac{5280}{7}{{m}^{2}}\]
B) \[\frac{5180}{7}{{m}^{2}}\]
C) \[\frac{4180}{7}{{m}^{2}}\]
D) \[\frac{3480}{7}{{m}^{2}}\]
Correct Answer: A
Solution :
Slant height \[=\sqrt{{{12}^{2}}+{{16}^{2}}}\] \[=\sqrt{400}=20m\] Canvas required = Curved surface area of conical tent \[=\pi rl=\frac{22}{7}\times 12\times 20\] \[=\frac{5280}{7}{{m}^{2}}\]
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