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Railways RRB (Assistant Loco Pilot & Technician) Solved Paper-2 (2014)

  • question_answer
    The maximum height is h to which a person can throw a ball. The maximum distance to which he can project it will be

    A)  \[h/2\]                         

    B)  h

    C)  \[3h/2\]                       

    D)  2h

    Correct Answer: D

    Solution :

    In projectile motion, height \[h=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] For maximum h, \[\theta ={{90}^{o}}\] Maximum height \[=\frac{{{u}^{2}}}{2g}=h\] Maximum range is obtained when angle of projection is \[{{45}^{o}}\]. Maximum range \[=\frac{{{u}^{2}}}{g}=2h\]


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