A) 11:40 a.m.
B) 12:40 p.m.
C) 1:40 p.m.
D) 2:40 p.m.
Correct Answer: D
Solution :
Let the tank will be emptied at\[x\]a.m. Tank filled by first pipe\[=\frac{1}{15}\times (x-8)\] Tank filled by second pipe\[=\frac{1}{12}\times (x-9)\] and tank emptied by third pipe\[=\frac{1}{4}\times (x-1)\] \[\therefore \] \[\frac{x-8}{15}+\frac{x-9}{12}=\frac{x-11}{4}\] \[\Rightarrow \] \[\frac{4x-32+5x-45}{60}=\frac{x-11}{4}\] \[\Rightarrow \] \[9x-77=15x-165\] \[\Rightarrow \] \[6x=88\] \[\therefore \] \[x=\frac{88}{6}=14\frac{2}{3}\] i.e. 2:40 p.m.
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