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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2011

  • question_answer
    The displacement \[y\] of a particle varies with time t, in second, as \[y=2\,\cos (\pi t+\pi /6)\]. The time period of the oscillations is

    A)  2s          

    B)  4s

    C)  1s                          

    D)         0.5s

    Correct Answer: A

    Solution :

                                    Given,\[y=2\cos (\pi t+\pi /6)\]                 Time period\[T=\frac{2\pi }{\omega }\]                 \[\omega =\pi \]it from the given equation                 \[T=\frac{2\pi }{\pi }\]                 \[T=2s\]


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