RAJASTHAN PMT Rajasthan - PMT Solved Paper-2011

  • question_answer
    A body is rotating with angular momentum L. If \[I\]is its moment of inertia about the axis of rotation, its kinetic energy of rotation is

    A) \[\frac{1}{2}I{{L}^{2}}\]                                

    B) \[\frac{1}{2}IL\]               

    C)        \[\frac{1}{2}{{I}^{2}}L\]                

    D)        \[\frac{1}{2}\frac{{{L}^{2}}}{I}\]

    Correct Answer: D

    Solution :

    We know that\[L=I\omega \] Kinetic energy of a body with angular momentum                 \[KE=\frac{1}{2}I{{\omega }^{2}}\]                 \[KE=\frac{1}{2}\times I\times {{\left( \frac{L}{I} \right)}^{2}}\]                 \[KE=\frac{{{L}^{2}}}{2I}\]


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