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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2011

  • question_answer
    Block A of mass 4 kg and block B of mass 6 kg are resting on a horizontal surface as shown in the figure. There is no friction between the block B and the horizontal surface. The coefficient of friction between the blocks is 0.2. If the value of \[g=10\,m/{{s}^{2}},\] the maximum horizontal force F that can be applied on block B without any relative motion between A and B is

    A)  20 N                                     

    B)  40 N                     

    C)  60 N                     

    D)         100 N

    Correct Answer: A

    Solution :

    We know that                 \[F=ma\] For combination of blocks \[m=10\,\,kg\]and\[a=2\,\,m/{{s}^{2}}\]                 \[F=10\times 2\]                 \[F=20\,\,N\]


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