A) \[41.29%\]
B) \[14.29%\]
C) \[20.29%\]
D) None of these
Correct Answer: B
Solution :
Percentage of the element or constituent no. of parts by mass \[=\frac{the\,\,element\,\,or\,\,constituent}{mol.\,\,mass\,\,of\,\,the\,\,compound}\times 100\] Molecular formula of ammonium dichromate is\[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\] mol. mass of\[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\] \[=2\times (14+4)+2\times 52\times 7\times 16=252\] No. of parts by mass of cation\[viz\,\,NH_{4}^{+}\] \[=2\times (14+4)=36\] \[\therefore \] % of\[NH_{4}^{+}=\frac{36}{252}\times 100\] \[=14.29%\]
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