A) \[N_{2}^{-},\,\,O_{2}^{2-}\]
B) \[N_{2}^{+},\,\,O_{2}^{-}\]
C) \[N_{2}^{-},\,\,O_{2}^{+}\]
D) \[O_{2}^{+},\,\,N_{2}^{2-}\]
Correct Answer: C
Solution :
Total no of electron in\[N_{2}^{-}\] \[=7+7+1=15\] Total no. of electron in\[N_{2}^{2-}\] \[=7+7+2=16\] Total no. of electron in\[N_{2}^{+}\] \[=7+7-1=13\] Total no. of electron in\[O_{2}^{-}\] \[=8+8+1=17\] Total no. of electron in\[O_{2}^{2-}\] \[=8+8+2=18\] Total no. of electron in\[O_{2}^{+}\] \[=8+8-1=15\] As \[N_{2}^{-}\] and \[O_{2}^{+}\] contains the same total no. of electrons, their MO electronic configuration will be same. Thus, \[N_{2}^{-}\] and \[O_{2}^{+}\] have the same bond order.
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