A) \[\text{13}\text{.6 }\!\!\times\!\!\text{ 1}\text{.6 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-19}}}\text{J}\]
B) \[\text{3}\text{.6 }\!\!\times\!\!\text{ 1}\text{.6 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-19}}}\text{J}\]
C) \[\text{1}\text{.51 }\!\!\times\!\!\text{ 1}\text{.6 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-19}}}\text{J}\]
D) zero
Correct Answer: B
Solution :
The electrostatic \[PE\] is zero when the electron and proton are far apart from each other. Work done in pulling electron and proton far away from each other. \[W={{E}_{f}}-{{E}_{i}}=0-{{E}_{i}}=-\left( -\frac{13.6}{{{n}^{2}}}eV \right)\] \[\Rightarrow \] \[W=\frac{13.6}{{{(2)}^{2}}}\times 1.6\times {{10}^{-19}}J\] \[=3.4\times 1.6\times {{10}^{-9}}J\]
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