A) 840 K
B) 280 K
C) 560 K
D) 373 K
Correct Answer: D
Solution :
Initially \[{{\eta }_{1}}=\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\] \[\Rightarrow \] \[0.5=\frac{{{T}_{1}}-(273+7)}{{{T}_{1}}}\] \[\Rightarrow \] \[\frac{1}{2}=\frac{{{T}_{1}}-280}{{{T}_{1}}}\] \[\Rightarrow \] \[{{T}_{1}}=560\,\,K\] Finally \[{{\eta }_{1}}=\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\] \[\Rightarrow \] \[0.7=\frac{{{T}_{1}}-(273+7)}{{{T}_{1}}}\] \[\Rightarrow \] \[{{T}_{1}}=933\,\,K\] \[\therefore \]Increase in temperature\[=933-560\] \[=373\,\,K\]
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