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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    The maximum peak to peak voltage of an AM wire is 24 mV and the minimum peak to peak voltage is 8 mV. The modulation factor is

    A)  10%                                      

    B)  20%

    C)  25%                      

    D)         50%

    Correct Answer: D

    Solution :

    Here,     \[{{V}_{\max }}=\frac{24}{2}=12\,\,mV\] and        \[{{V}_{\min }}=\frac{8}{2}=4\,\,mV\] Now,     \[m=\frac{{{V}_{\max }}-{{V}_{\min }}}{{{V}_{\max }}+{{V}_{\min }}}=\frac{12-4}{12+4}\]                 \[=\frac{8}{16}=\frac{1}{2}=0.5=50%\]


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