A) \[3.8\,\times {{10}^{7}}m/s\]
B) \[\text{1}\text{.9 }\!\!\times\!\!\text{ 1}{{\text{0}}^{6}}\text{m/s}\]
C) \[\text{1}\text{.9 }\!\!\times\!\!\text{ 1}{{\text{0}}^{7}}\text{m/s}\]
D) \[\text{5}\text{.7 }\!\!\times\!\!\text{ 1}{{\text{0}}^{7}}\text{m/s}\]
Correct Answer: C
Solution :
If the voltage given is\[V\], then the energy of electron \[=\frac{1}{2}m{{v}^{2}}=eV\] \[v=\sqrt{\frac{2eV}{m}}\] \[=\sqrt{\frac{2\times 1.6\times {{10}^{-19}}\times 1000}{9.1\times {{10}^{-31}}}}\] \[=1.875\times {{10}^{7}}\] \[=1.9\times {{10}^{7}}\,\,m/s\]
You need to login to perform this action.
You will be redirected in
3 sec
