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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    A cylinder of fixed capacity 44.8 L contains a monoatomic gas at standard temperature and pressure. The amount of heat required to raise the temperature of cylinder by \[10{}^\circ C\] will be (R = universal gas constant)

    A)  R                                           

    B)  10 R

    C)  20 R                      

    D)         30 R

    Correct Answer: D

    Solution :

    As we know 1 mole of any ideal gas at STP occupies a volume of\[22.4\,\,L\] Hence, number of moles of gas\[\mu =\frac{44.8}{22.4}=2\] Since, the volume of cylinder is fixed. Hence,\[{{(\Delta Q)}_{V}}=\mu {{C}_{V}}\Delta T\] \[=2\times \frac{3}{2}R\times 10=30R\left( \because {{({{C}_{V}})}_{mono}}=\frac{3}{2}R \right)\]


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