A) \[2\times {{10}^{6}}\,N/{{m}^{2}}\]
B) \[3\times {{10}^{6}}\,N/{{m}^{2}}\]
C) \[4\times {{10}^{6}}\,N/{{m}^{2}}\]
D) \[5\times {{10}^{6}}\,N/m\]
Correct Answer: D
Solution :
The average kinetic energy of gas molecules \[E=\frac{3}{2}pV\] So, the pressure of hydrogen in the cylinder \[p=\frac{2E}{3V}=\frac{2}{3}\times \frac{1.52\times {{10}^{5}}}{20\times {{10}^{-3}}}\] \[=\frac{{{10}^{5}}}{20\times {{10}^{-3}}}=5\times {{10}^{6}}N/{{m}^{2}}\]
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