A) \[9.58\,\times {{10}^{-5}}J\]
B) \[8.95\,\times {{10}^{-5}}J\]
C) \[5.89\,\times {{10}^{-5}}J\]
D) \[5.98\,\times {{10}^{-6}}J\]
Correct Answer: B
Solution :
Work done in splitting a water drop of radius \[R\] into \[n\] drops of equal size \[=4\pi {{R}^{2}}T({{n}^{1/3}}-1)\] \[=4\pi \times {{({{10}^{-3}})}^{2}}\times 72\times {{10}^{-3}}\times ({{10}^{6/3}}-1)\] \[=4\pi \times {{10}^{-6}}\times 72\times {{10}^{-3}}\times 99\] \[=8.95\times {{10}^{-5}}J\]
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