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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    A \[\text{10}\,\text{F}\] capacitor is charged to a potential difference of 1000 V. The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged 6uF capacitor. What is the final potential difference across each capacitor?

    A)  167 V                                   

    B)  100 V

    C)  625 V                   

    D)         250 V

    Correct Answer: C

    Solution :

    After charging, total charge on the capacitor                 \[Q=CV\]                 \[=10\times {{10}^{-6}}F\times 1000\,\,V\]                 \[={{10}^{-2}}C\] Common potential\[V=\frac{{{C}_{1}}{{V}_{1}}}{{{C}_{1}}+{{C}_{2}}}\]                                       \[=\frac{{{10}^{-2}}}{16\times {{10}^{-6}}}=625\,\,V\]


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