RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    Each resistance shown in the circuit is of\[10\,\Omega \]. The equivalent resistance between the points X and Y is

    A)  \[10\,\Omega \]

    B)                                         \[20\,\Omega \]

    C)  \[25\,\Omega \]             

    D)         \[30\,\Omega \]

    Correct Answer: A

    Solution :

    In arm\[ABC\], resultant resistance                 \[R={{R}_{1}}+{{R}_{2}}=10+10=20\Omega \] In arm\[ADC\], resultant resistance                 \[R\,\,={{R}_{3}}+{{R}_{4}}=10+10=20\Omega \] Resistances \[R\] and \[R\,\,\] are in parallel, \[\therefore \]  \[\frac{1}{R}=\frac{1}{R}+\frac{1}{R\,\,}=\frac{1}{20}+\frac{1}{20}\]                 \[R=10\Omega \].


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