RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    If\[{{\theta }_{i}}\]is the inversion temperature,\[{{\theta }_{n}}\]is the neutral temperature, \[{{\theta }_{c}}\]is the temperature of the cold junction for thermocouple, then

    A)  \[{{\theta }_{i}}+{{\theta }_{c}}={{\theta }_{n}}\]

    B)                         \[{{\theta }_{i}}-{{\theta }_{c}}=2{{\theta }_{n}}\]

    C)  \[\frac{{{\theta }_{i}}+{{\theta }_{c}}}{2}\theta n\]       

    D)         \[{{\theta }_{c}}-{{\theta }_{i}}=2{{\theta }_{n}}\]

    Correct Answer: C

    Solution :

                    \[{{\theta }_{n}}-{{\theta }_{c}}={{\theta }_{i}}-{{\theta }_{n}}\] or            \[{{\theta }_{n}}=\frac{{{\theta }_{i}}+{{\theta }_{c}}}{2}\]


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