RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    An alternating potential of frequency\[f\]is applied on a circuit containing a resistance R and a choke L in series. The impedance of this current is

    A)  \[R+2\pi fL\]                     

    B)  \[\sqrt{{{R}^{2}}+4{{\pi }^{2}}{{f}^{2}}{{L}^{2}}}\]

    C)  \[\sqrt{{{R}^{2}}+{{L}^{2}}}\]      

    D)         \[\sqrt{{{R}^{2}}+2\pi fL}\]

    Correct Answer: B

    Solution :

    Impedance of the circuit\[(Z)=\sqrt{{{R}^{2}}+X_{L}^{2}}\]                 \[=\sqrt{{{R}^{2}}+{{(L\omega )}^{2}}}\]                 \[=\sqrt{{{R}^{2}}+{{(L\cdot 2\pi f)}^{2}}}\]                 \[=\sqrt{{{R}^{2}}+4{{\pi }^{2}}{{f}^{2}}{{L}^{2}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner