A) 2
B) 4
C) 3
D) 1
Correct Answer: C
Solution :
Ionization of\[[Co{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{2}}\] is as follows \[[Co{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{2}}{{[Co{{(N{{H}_{3}})}_{4}}Cl]}^{2+}}+2C{{l}^{-}}\]It give three ions.
You need to login to perform this action.
You will be redirected in
3 sec
