A) \[a\]
B) \[a/2\]
C) \[\frac{\sqrt{3}}{4}a\]
D) \[\frac{2a}{\sqrt{3}}\]
Correct Answer: C
Solution :
\[CsCl\] has body centred cubic arrangement For body centred cubic arrangement \[a=\frac{4r}{\sqrt{3}}\] \[\therefore \] \[r=\frac{\sqrt{3}}{4}a\] where,\[r=\]interionic distance and\[a=\]edge length of cube.
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