A) ethylamine
B) methylamine
C) dimethylamine
D) trimethylamine
Correct Answer: C
Solution :
Reduction of alkyl isocyanide give secondary amine \[\underset{\begin{smallmatrix} \text{methyl} \\ \text{isocyanide} \end{smallmatrix}}{\mathop{C{{H}_{3}}-NC}}\,\xrightarrow[4[H]]{Na/{{C}_{2}}{{H}_{5}}OH}\underset{\text{dimethyl}\,\,\text{amine}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{N}}\,-H}}\,\]
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