RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    If an organic compound has\[C=40%\], \[H=13.3%\],\[N=46.67%\] , then the empirical formula for this compound is

    A) \[C{{H}_{4}}N\]                

    B)        \[{{C}_{2}}{{H}_{8}}{{N}_{2}}\]                  

    C)        \[C{{H}_{3}}N\]                

    D)        None of these

    Correct Answer: A

    Solution :

    Element C H N
    Percentage \[40.00%\] \[13.33%\] \[46.67%\]
    Relative ratio of atoms \[\frac{40}{12}\] \[=3.33\] \[\frac{13.33}{1}\] \[=13.33\] \[\frac{46.67}{14}\] \[=3.33\]
    Simple ratio of atom \[\frac{3.33}{3.33}\] \[=1\] \[\frac{13.33}{3.33}\] \[=4\] \[\frac{3.33}{3.33}\] \[=1\]
    So, empirical formula is\[C{{H}_{4}}N\].


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