RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    An ideal transformer has 500 rums in the primary and 2500 in the secondary. The meters of the secondary are indicating 200 V, 8 A, under these conditions. What would the meters of the primary read?

    A)  100 V, 16 A      

    B)         40 V, 40 A

    C)  160 V, 10 A      

    D)         80 V, 20 A

    Correct Answer: B

    Solution :

    Given,\[{{N}_{p}}=500\] turns,\[{{N}_{s}}=2500,\,\,{{I}_{s}}=8\,\,A\],\[{{e}_{s}}=200\,\,volt\] Transformation ratio\[(k)=\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{{{e}_{s}}}{{{e}_{p}}}=\frac{{{I}_{p}}}{{{I}_{s}}}\] \[\therefore \]  \[\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{{{e}_{s}}}{{{e}_{p}}}\frac{2500}{500}=\frac{200}{{{e}_{p}}}\] \[\therefore \]  \[{{e}_{p}}=40\,\,volt\] Again,   \[\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{{{I}_{p}}}{{{I}_{s}}}\]                 \[\frac{2500}{500}=\frac{{{I}_{p}}}{8}\]                 \[{{I}_{p}}=40\,\,A\]


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