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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2009

  • question_answer
    A body moves a distance of 10 m along a straight line under the action of a force of 5 N. If the work done is 25 J the angle, which the force makes with the direction of motion of the body is

    A)  \[0{}^\circ \]                                     

    B) \[30{}^\circ \]

    C) \[60{}^\circ \]                   

    D)        \[90{}^\circ \]

    Correct Answer: C

    Solution :

    Given,\[s=10\,\,m,\,\,F=5N,\,\,W=25\,\,J,\,\,\theta =?\] Work done,\[W=Fs\cos \theta \] \[\therefore \]  \[\cos \theta =\frac{W}{Fs}=\frac{25}{5\times 10}=\frac{1}{2}\]                 \[=\cos {{60}^{o}}\,\,\,\,\therefore \theta ={{60}^{o}}\]


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