A) \[3\]
B) \[4\]
C) \[5\]
D) \[6\]
Correct Answer: D
Solution :
\[F{{e}_{26}}\cdot [Ar]3{{d}^{6}}4{{s}^{2}}F{{e}^{2+}}(24\,\,electrons)-[Ar]3{{d}^{6}}4{{s}^{0}}\]
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