A) \[\Delta G=RT\ln {{K}_{c}}\]
B) \[-\Delta G=RT\ln {{K}_{c}}\]
C) \[\Delta {{G}^{o}}=RT\ln {{K}_{c}}\]
D) \[-\Delta {{G}^{o}}=RT\ln {{K}_{c}}\]
Correct Answer: A
Solution :
\[\Delta {{G}^{o}}=-{{W}_{\max }}\]. Maximum work done by the system.
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