A) \[4\times {{10}^{-15}}\]
B) \[4\times {{10}^{-10}}\]
C) \[1\times {{10}^{-15}}\]
D) \[1\times {{10}^{-10}}\]
Correct Answer: A
Solution :
\[A{{B}_{2}}\underset{S}{\mathop{{{A}^{2+}}}}\,+\underset{2S}{\mathop{2{{B}^{-}}}}\,\] \[{{K}_{sp}}=[{{A}^{2+}}]{{[{{B}^{-}}]}^{2}}\] \[=(S){{(2S)}^{2}}=4{{S}^{3}}\] \[=4{{(1\times {{10}^{-5}})}^{3}}\] \[=4\times {{10}^{-15}}\]
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