A) \[50\min \]
B) \[100\min \]
C) \[99\min \]
D) \[150\min \]
Correct Answer: C
Solution :
Radioactive disintegration is a 1st order reaction, hence \[k=\frac{2.303}{t}\log \frac{a}{a-x}\] \[\therefore \] \[k=\frac{2.303}{15}\log \frac{100}{100-50}\] also \[k=\frac{2.303}{t}\log \frac{100}{100-99}\] \[\therefore \]\[\frac{2.303}{15}\log \frac{100}{50}=\frac{2.303}{t}\log \frac{100}{1}\] \[\frac{1}{15}\log 2=\frac{1}{t}\log 100\] \[\frac{0.3010}{15}=\frac{2}{t}\] \[t=\frac{2\times 15}{0.3010}=99\,\,\min \]
You need to login to perform this action.
You will be redirected in
3 sec
