2. Solved Papers
  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-2008

  • question_answer
    In an oxidation-reduction reaction, \[MnO_{4}^{-}\] ion is converted to\[M{{n}^{2+}}\]. What is the number of equivalents of\[KMn{{O}_{4}}\] (mol. wt. =158) present in \[250\,\,mL\] of \[0.04\,\,M\,\,KMn{{O}_{4}}\] solution?

    A) \[0.02\]                               

    B)        \[0.05\]

    C)        \[0.04\]                               

    D)        \[0.07\]

    Correct Answer: B

    Solution :

    Change in oxidation number\[(+7)-(+2)=5\] \[\therefore \]Normality of solution\[=5\times 0.04=0.20\,\,N\] Volume\[=250\,\,mL\] \[\therefore \]Number of equivalents of\[KMn{{O}_{4}}\]                 \[=0.20\times \frac{250}{1000}=0.05\]


You need to login to perform this action.
You will be redirected in 3 sec spinner