A) 12 m
B) 18 m
C) 24 m
D) 6 m
Correct Answer: C
Solution :
\[{{v}^{2}}={{u}^{2}}+2as\] \[0={{\left( 50\times \frac{5}{18} \right)}^{2}}+2a\times 6\] \[a=-16\,\,m/{{s}^{2}}\] (\[a=\]retardation) Again \[{{v}^{2}}={{u}^{2}}+2as\] \[0={{\left( 100\times \frac{5}{18} \right)}^{2}}-16\times 2\times s\] \[s=\frac{{{(100\times 5)}^{2}}}{18\times 18\times 32}\approx 24\,\,m\]
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