A) 1000
B) 10000
C) 10
D) 100
Correct Answer: D
Solution :
Let intensity of sound be \[I\] and \[I\] Loudness of sound initially \[{{\beta }_{1}}=10\log \left( \frac{I}{{{I}_{0}}} \right)\] Later, \[{{\beta }_{2}}=10\log \left( \frac{I}{{{I}_{0}}} \right)\] Given, \[{{\beta }_{2}}-{{\beta }_{1}}=20\] \[\therefore \] \[20=10\log \left( \frac{I}{I} \right)\] \[\therefore \] \[I=100I\]
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