A) 0.40 g
B) 0.50 g
C) 0.67 g
D) 0.27 g
Correct Answer: D
Solution :
Key Idea Apply first law of electrolysis during deposition of charge on an electrode through electrolysis. If \[m\] is the mass of a substance deposited or liberated at an electrode during electrolysis when a charge q passes through electrolyte, then according to Faradays first law of electrolysis, \[m\propto q\] or \[m=zq\] where \[z\] is a constant of proportionality and is called electrochemical equivalent (ECE) of the substance. If an electric current \[I\] flows through the electrolyte, then \[q=It\] \[m=zit\] Here,\[i=1.5\,\,A,\,\,t=10\min =10\times 60s\], \[z=30\times {{10}^{-5}}g\,\,{{C}^{-1}}\] Hence, mass of copper deposited on the electrode \[m=30\times {{10}^{-5}}\times 1.5\times 10\times 60\] \[=27\times {{10}^{-2}}=0.27\,\,g\]
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