RAJASTHAN PMT Rajasthan - PMT Solved Paper-2007

  • question_answer
    A diseased man marries a normal woman and they get three daughters and five sons. All the daughters were diseased and sons were normal. The gene of this diseases is

    A)  sex-linked dominant    

    B)  sex-linked recessive

    C)  sex-limited character

    D)  autosomal dominant

    Correct Answer: A

    Solution :

    Since the father is diseased and daughters also-the diseases is not sex-limited of course, it is sex-linked. Sex linked inheritance may be X-linked as given in the question. Y-linked and XY-linked. In X-linked inheritance the characters are controlled by genes located on non-homologous part of X-chromosome. These X-linked genes do not have their corresponding alleles on Y-chromosome. In daughter it is express even when present in heterozygous condition.


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