A) butanol-1
B) butanol-2
C) 2-methyl-propanol-2
D) 2-methyl-propanol-1
Correct Answer: C
Solution :
The order of reactivity with alcohols with lucas reagent is \[3{}^\circ >2{}^\circ >1{}^\circ \] \[\therefore \]Lucas reagent reacts fastest with \[3{}^\circ \] alcohol. (a)\[\underset{\text{butanol}-1({{1}^{o}}alcohol)}{\mathop{C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}OH}}\,\] (b)\[\underset{\text{butanol}-2({{2}^{o}}alcohol)}{\mathop{C{{H}_{3}}-C{{H}_{2}}-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}}}\,\] (c)\[\underset{2methyl\,\,2-propanol\,\,({{3}^{o}}alcohol)}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}}}\,\] (d)\[\underset{2-methyl\,\,1-propanol\,\,({{1}^{o}}alcohol)}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}OH}}\,\] \[\therefore \]choice (c) is the answer as it is \[{{3}^{o}}\] alcohol and rate of reaction is fastest for \[{{3}^{o}}\] alcohol.
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