A) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}\]
B) \[C{{H}_{3}}-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}\]
C) \[{{(C{{H}_{3}})}_{3}}C-C{{H}_{2}}OH\]
D) none of the above
Correct Answer: B
Solution :
Only \[{{1}^{o}}\] and \[{{2}^{o}}\] alcohol are oxidized by alkaline \[KMn{{O}_{4}}\cdot {{3}^{o}}\] alcohols do not react with alkaline\[KMn{{O}_{4}}\] \[\underset{{{2}^{o}}alcohol}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} OH \\ | \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{3}}}}\,\xrightarrow{Alk.\,\,KMn{{O}_{4}}}\underset{ketone}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ |\,\,| \end{smallmatrix}}{\mathop{C}}\,-CH}}\,\] \[\xrightarrow{alk.\,\,KMn{{O}_{4}}}\underset{acid}{\mathop{C{{H}_{3}}COOH}}\,\]
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