A) more resistance
B) less resistance
C) zero resistance
D) none of these
Correct Answer: B
Solution :
At a higher frequency, the charge on the capacitor plates will vary more rapidly, so\[\left( \frac{dq}{dt} \right)\] will be higher resulting in an increase in the instantaneous current\[\left( i=\frac{dq}{dt} \right)\]. This means lower capacitive reactance\[ie\], less resistance.
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